7(x^2+6)=42

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Solution for 7(x^2+6)=42 equation: 



7(x^2+6)=42

We move all terms to the left:

7(x^2+6)-(42)=0

We multiply parentheses

7x^2+42-42=0

We add all the numbers together, and all the variables

7x^2=0

a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{14}=0$

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